Aké sú nuly kvadratickej rovnice x ^ 2 + 5x = -6?

odpoveď:

Nula na # X = -2 # a # X = -3 #

vysvetlenie:

# X ^ 2 + 5 x = -6 #

#hArrcolor (biely) ("XXX") x ^ x + 5x + 6 = 0 #

#hArrcolor (biely) ("XXX") (x + 2) (x + 3) = 0 #

buď

#COLOR (biely) ("XXX") (x + 2) = 0color (biely) ("XX") rarrcolor (biely) ("XX") x = -2 #

alebo

#COLOR (biely) ("XXX") (x + 3) = 0color (biely) ("XX") rarrcolor (biely) ("XX") x = -3 #