Aký je podiel d-2 delený d ^ 4-6d ^ 3 + d + 17?

odpoveď:

Kvocient je # = (D ^ 3-4d ^ 2-8d-15) #

Vykonajme dlhé rozdelenie

# D-2 ##COLOR (biely) (AAAA) ##|## D ^ 4-6d ^ 3 + 0d ^ 2 + d + 17 ##COLOR (biely) (aa) ##|## D ^ 3-4d ^ 2-8d-15 #

#COLOR (biely) (aaaaaaaaaa) ## D ^ 4-2d ^ 3 #

#COLOR (biely) (aaaaaaaaaaa) ## 0-4d ^ 3 + 0d ^ 2 #

#COLOR (biely) (aaaaaaaaaaaaa) ## -4d ^ 3 + 8 d ^ 2 #

#COLOR (biely) (aaaaaaaaaaaaaa) ## -0-8d ^ 2 + d #

#COLOR (biely) (aaaaaaaaaaaaaaaaa) ## -8d ^ 2 + 16d #

#COLOR (biely) (aaaaaaaaaaaaaaaaaaa) ## -0-15d + 17 #

#COLOR (biely) (aaaaaaaaaaaaaaaaaaaaaaa) ## -15d + 30 #

#COLOR (biely) (aaaaaaaaaaaaaaaaaaaaaaaaa) ##-0-13#

Z tohto dôvodu

# (D ^ 4-6d ^ 3 + d + 17) / (d-2) = d ^ 3-4d ^ 2-8d-15-13 / (d-2) #

Zvyšok je #=-13# a kvocient je # = (D ^ 3-4d ^ 2-8d-15) #